# How do you graph the line #3x-4y-8=0#?

##### 3 Answers

you will have to graph the line

where

#### Explanation:

you would have to rearrange the given equation into the

form, where

graph{3/4x-2 [-10, 10, -5, 5]}

As below.

#### Explanation:

For x = 0, -4y - 8 = 0 " or " y-intercept = -2#

For y = 0, 3x = 8 " or " x-intercept = 8/3#

Now we know, x intercept as 8/3 and y intercepts as -2#

We can mark the intercepts on the graph and join them to draw the line.

graph{(3/4)x - 2 [-10, 10, -5, 5]}

Graph the line by finding the intercepts.

#### Explanation:

Graph:

Add

You can graph this equation by finding the intercepts.

**X-intercept: value of #x# when #y=0#**

Substitute

Divide both sides by

**The x-intercept is #(8/3,0)# or #~~2.667# Plot this point.**

**Y-intercept: value of #y# when #x=0#.**

Substitute

Divide both sides by

Simplify.

**The y-intercept is #(0,-2)# Plot this point.**

Draw a straight line through the points.

graph{3x-4y=8 [-10, 10, -5, 5]}