# How do you graph the line #x+2y=4#?

##### 2 Answers

#### Answer:

#### Explanation:

As you have two different variables (x and y) you aren't looking at a linear function but at a 3d function instead. Make sure you have the correct heading (or perhaps its mistaken in your book?)!

However, this is what it'd look like:

If the heading was mistaken or you copied it down incorrectly, and you have a new linear graph you don't know how to plot, please let me know and I'll try to help you out :)

#### Answer:

Identify the

#### Explanation:

Given:

#x+2y = 4#

Note that this equation is linear, since all of the terms in

We can find the line's

#x = 4#

So the intersection with the

Similarly, we can find the line's

#2y=4#

and hence:

#y = 2#

So the intersection with the

Now we can draw our line through those two points:

graph{(x+2y-4)((x-4)^2+y^2-0.02)(x^2+(y-2)^2-0.02) = 0 [-7.58, 12.42, -4.04, 5.96]}