How do you graph the line y = 2/3x + 4?

Sep 6, 2016

• Start at the point $\left(0 , 4\right)$ then go up two and three to the right.
Repeat and connect the points with a straight line.

Explanation:

Use the y = mx + b form. b is the y intercept - the place where the line crosses the y-axis. ( b = beginning)

The y intercept is the point where $x = 0$

In this equation $b = 4$. This is the y intercept where $x = 0$

So the point to start graphing from is $\left(0 , 4\right)$
The x-value is always first in a point $\left(x , y\right)$

The slope is the angle at which the line leans.

This is the $m$ in the the $y = m x + b$ equation.
(m = mountain slope)

In this equation, $m = \frac{2}{3}$

Slope equals $\frac{\Delta y}{\Delta x}$ so $y = 2 \mathmr{and} x = 3.$

$y$ is the up and down value so the line moves up 2 points.
( 2 is positive so the line goes up 2: if the value was -2 the line would go down 2)

$x$ is the right and left value so the line moves three points to the right.
(3 is positive so the line goes to the right:
If the value was negative the line would go to the left.)

Count 2 up and three to the right and make a point,
Do this procedures several times starting at $\left(0 , 4\right)$
The points will connect in a straight line.