How do you graph the parabola #(x+2)^2=-8(y-1)# using vertex, intercepts and additional points?
1 Answer
Feb 28, 2018
Refer Explanation section
Explanation:
Given -
#(x+2)^2=-8(y-1)#
The given equation is in the vertex form
#(x-h)^2=4a(y-k)#
Where vertex is
In the given equation the vertex is
Take a few value on either side of
Find the corresponding
Tabulate them.
Plot the points and obtain the curve.
#y=[1/8(x+2)^2]+1#
