How do you graph the parabola #y = (x-2)^2 +2# using vertex, intercepts and additional points?

Question

3286 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-07T18:13:37

enter image source here

#y-2=(x-2)^2#
It is of the form #Y=4AX^2# [an upward parabola]

enter image source here

Vertex is (2,2)

*For y intercept put x=0 we get y=6 *

Some points (0,6),(2,2) (4,6)

enter image source here

Final Graph
enter image source here