How do you graph the point #D(-2,(13pi)/6)#?
1 Answer
Jan 22, 2017
See the small circle representing the point of zero radius, at D.
graph{(x+sqrt3)^2+(y+1)^2-.01=0 [-10, 10, -5, 5]}
Explanation:
In cartesian form, it is
Using Socratic utility, mark the point by a circle of small radius, with
center at D
