# How do you graph the point #E(2,30^o)#?

##### 1 Answer

In cartesian form, it is

The first graph is for dotting the point. In the second, it is the intersection in

#### Explanation:

graph{(x-1.732)^2+(y-1)^2-10^(-4)=0x^2 [-3, 3, -1.5, 1.5]}

For dotting the point by glow of pixels, use a circle with center at the

point and radius suitably quite small., say 0.01. This would enable a

few pixels (3 or 4 in two rows or 7 in three rows ) to glow, at the

point.

Here, the equation of the point circle is

Alternative method that suits polar frame:

I have used the equation

the equation

The intersection in

graph{(x^2+y^2-4)(1.732y-(x+|x|)/2)=0 [-6, 6, -3, 3]}

For locating

intersection of

the circle