How do you graph the point #E(2,30^o)#?
1 Answer
In cartesian form, it is
The first graph is for dotting the point. In the second, it is the intersection in
Explanation:
graph{(x-1.732)^2+(y-1)^2-10^(-4)=0x^2 [-3, 3, -1.5, 1.5]}
For dotting the point by glow of pixels, use a circle with center at the
point and radius suitably quite small., say 0.01. This would enable a
few pixels (3 or 4 in two rows or 7 in three rows ) to glow, at the
point.
Here, the equation of the point circle is
Alternative method that suits polar frame:
I have used the equation
the equation
The intersection in
graph{(x^2+y^2-4)(1.732y-(x+|x|)/2)=0 [-6, 6, -3, 3]}
For locating
intersection of
the circle