How do you graph the quadratic function and identify the vertex and axis of symmetry for #y=-1/6x^2+x-3#?
As the coefficient of
There is no stipulation in the question about how you are to determine the information so I chose the following method
As the graph is of form
The curve doe NOT cross the x-axis.
So there is no solution to
The axis of symmetry passes through the vertex so it has the x value as the vertex.