# How do you graph using slope and intercept of 4x-2y=48?

Jun 18, 2018

Put it into the form $y = m x + c$

$4 x = 2 y + 48$

$4 x - 48 = 2 y$

$2 x - 24 = y$

$y = 2 x - 24$

slope is 2 and the intercept is (0,-24)

Jun 18, 2018

See below for graph and method

#### Explanation:

Re-arranging the given equation: $4 x - 2 y = 48$ into slope-intercept form:
$\textcolor{w h i t e}{\text{XXX}} 4 x - 48 = 2 y$

$\textcolor{w h i t e}{\text{XXX}} y = 2 x - 24$
$\textcolor{w h i t e}{\text{XXX}}$ which is the slope intercept form
$\textcolor{w h i t e}{\text{XXX}}$ with slope $2$, and
$\textcolor{w h i t e}{\text{XXX }} y$-intercept $\left(- 24\right)$

The $y$ intercept of $\left(- 24\right)$ tells us that one of the points on our line is at $\left({x}_{0} , {y}_{0}\right) = \left(0 , - 24\right)$

The slope of $2$ tells us that for every increase of $1$ in the value of $x$, the value of $y$ will increase by $2$.
So some other points that we could use to plot out line are:
$\textcolor{w h i t e}{\text{XXX}} \left({x}_{1} , {y}_{1}\right) = \left(0 + 1 , - 24 + 2\right) = \left(1 , - 22\right)$
or
$\textcolor{w h i t e}{\text{XXX}} \left({x}_{24} , {y}_{24}\right) = \left(0 + 24 , - 24 + \left(2 \cdot 24\right)\right) = \left(24 , 24\right)$

graph{(x^2+(y+24)^2-0.3)((x-1)^2+(y+22)^2-0.3)((x-24)^2+(y-24)^2-0.3)(4x-2y-48)=0 [-50.63, 81, -40.23, 25.64]}