How do you graph using slope and intercept of 5x+3y=19?

1 Answer
Sep 25, 2016

y = -5/3 x + 19/3
Plot c " at " 6 1/3 and count (Delta y)/(Delta x) " as " -5/3

Explanation:

Write the equation of the straight line in the form of #y = mx + c" first

5x +3y = 19

3y = -5x +19

y = -5/3 x + 19/3" "rarr 19/3 =6 1/3

This means that the y-intercept is at 6 1/3

Start the graph by marking that point.
the slope is -5/3

From 6 1/3, count UP 5 units and 3 to the LEFT, mark a point.
Again, count UP 5 units and 3 to the LEFT, mark a point.

From 6 1/3, count DOWN 5 units and 3 to the RIGHT, mark a point.
Again, count DOWN 5 units and 3 to the RIGHT, mark a point.

This will give you 5 points which you can use to draw the straight line. Remember to write the equation on the line.

graph{y= -5/3 x+ 19/3 [-11.71, 8.29, 3.1, 13.1]}