How do you graph using slope and intercept of 5x+3y=19?

Sep 25, 2016

$y = - \frac{5}{3} x + \frac{19}{3}$
Plot $c \text{ at } 6 \frac{1}{3}$ and count $\frac{\Delta y}{\Delta x} \text{ as } - \frac{5}{3}$

Explanation:

Write the equation of the straight line in the form of #y = mx + c" first

$5 x + 3 y = 19$

$3 y = - 5 x + 19$

$y = - \frac{5}{3} x + \frac{19}{3} \text{ } \rightarrow \frac{19}{3} = 6 \frac{1}{3}$

This means that the y-intercept is at $6 \frac{1}{3}$

Start the graph by marking that point.
the slope is $- \frac{5}{3}$

From $6 \frac{1}{3}$, count UP 5 units and 3 to the LEFT, mark a point.
Again, count UP 5 units and 3 to the LEFT, mark a point.

From $6 \frac{1}{3}$, count DOWN 5 units and 3 to the RIGHT, mark a point.
Again, count DOWN 5 units and 3 to the RIGHT, mark a point.

This will give you 5 points which you can use to draw the straight line. Remember to write the equation on the line.

graph{y= -5/3 x+ 19/3 [-11.71, 8.29, 3.1, 13.1]}