# How do you graph using slope and intercept of -7x-2y= -5?

Nov 12, 2015

Plotting y-intercept= $\frac{5}{2}$ and drawing 16 degrees angle towards positive x-axis.

#### Explanation:

Let's write the given equation in y = mx +c form
y = -$\frac{7}{2}$x + $\frac{5}{2}$
here the y intercept = $\frac{5}{2}$
Slope = -$\frac{7}{2}$x
graph{-7x-2y = -5 [-10, 10, -5, 5]}
Mark at 2.5 to mark the y-intercept. Since the slope is -7/2. ${\tan}^{-} 1$ (7/2) = 74.04 degrees. Negative value of ${\tan}^{-} 1$ (-7/2) = (180 - 76)= 106. Interior angle at 2.5 will be 16 degrees. Draw 16 degrees from 2.5 intercept. The line which passes through x-axis will be the required equation.