# How do you graph using slope and intercept of 8y-7x=13?

Jun 2, 2018

$y = \frac{7}{8} x + \frac{13}{8}$ [original, as fractions]
$y = 0.875 x + 1.625$ [as decimals]

#### Explanation:

$8 y - 7 x = 13$

The goal is to make $8 y - 7 x = 13$ into $y = m x + b$ format in order to easily graph it. To do this, we're going to rearrange the current equation.

$8 y - 7 x = 13$

First, let's make $- 7 x$ to go the other side so that way the equation comes closer to the $y = m x + b$ form. To do this, add $7 x$ to both sides to cancel out $- 7 x$. You should now have:

$8 y = 7 x + 13$

Now, we need to isolate for $y$. To do this, divide $8 y$ by $8$. Because you must do to one side to the other, you'll divide the entire equation by $8$.

$y = \frac{7}{8} x + \frac{13}{8}$
$\frac{7}{8} x$ is your slope and $\frac{13}{8}$ is your y-intercept. To make it easier to calculate, I'll convert them into decimals.

$y = 0.875 x + 1.625$

You can either graph it by estimating using the decimals provided, or you can use the original version with rise over run. Here's what it looks like:

graph{y = 7/8x + 13/8 [-12.66, 12.65, -6.33, 6.33]}