How do you graph using the intercepts for #4x + 3y = -21#?

1 Answer
Jun 12, 2018

Answer:

#"see explanation"#

Explanation:

#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArr3y=-21rArry=-7larrcolor(red)"y-intercept"#

#y=0rArr4x=-21rArrx=-21/4larrcolor(red)"x-intercept"#

#"plot the points "(0,-7)" and "(-21/4,0)#

#"draw a straight line through them for graph"#
graph{(y+4/3x+7)((x-0)^2+(y+7)^2-0.04)((x+21/4)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}