Question

How do you graph using the intercepts for `7x+2y=24`?

Answer 1

Plot the intercept points `(0,12)` and `(3 3/7,0)` then draw a straight line through the two points

Explanation:

The y-intercept is the value of `y` when `x=0`
`color(white)("XXX")7(0)+2y=24 rArr y=12`
`color(white)("XXX")`y-intercept is at `(0,12)`

Similarly the x-intercept is the value of `x` when `y=0`
`color(white)("XXX")7x+2(0)=20 rArr x= 3 3/7`
`color(white)("XXX")`x-intercept is at `(3 3/7,0)`

The graph should look like:
graph{(7x+2y-24)(x^2+(y-12)^2-0.05)((x-(24/7))^2+y^2-0.05)=0 [-17.7, 22.83, -6.99, 13.29]}