How do you graph (x-1)(x+4)-y=0?

1 Answer
Feb 1, 2018

Look below

Explanation:

(x-1)(x+4)-y=0 can be simpified as

x^2+3x-4=y

now since we have a quadratic, label a, b, and c.

a=1
b=3
c=4 -- this is the y-intercept

now use the formula (-b)/(2a) to find the symmetrical line (which is imaginary)

\frac{-3}{2(1)}=\frac{-3}{2}

now use that to substitute x, which will be ur y

Btw, x is -3/2

now, (\frac{-3}{2})^2+3(\frac{-3}{2})-4

=\frac{-25}{4}

(\frac{-3}{2}, \frac{-25}{4})

GRAPH
graph{x^2+3x-4 [-9.29, 10.71, -8, 2]}

Your graph should look like that.