Question

How do you graph `x^2+y^2-1=0`?

Answer 1

`x^2+y^2-1=0` is a circle with center at the origin and radius `1`

Explanation:

`x^2+y^2-1=0color(white)("XX")rArrcolor(white)("XX")x^2+y^2=1^2`

Any equation of the form `x^2+y^2=r^2` is a circle with center at the origin i.e. at `(0,0)` with a radius of `r`