How do you graph x^2 + y^2 = 16?

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Explanation

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Explanation:

I want someone to double check my answer

8
Jan 26, 2016

This is going to be the graph of a circle with the center at the origin and a radius of 4.
graph{x^2+y^2-16=0 [-11.25, 11.25, -5.625, 5.625]}

Explanation:

The formula for a circle is:

${\left(x - {x}_{c}\right)}^{2} + {\left(y - {y}_{c}\right)}^{2} = {r}^{2}$

The center of this circle will be located at the point (x_c, y_c).

You can expand your equation above to look like this:

${\left(x - 0\right)}^{2} + {\left(y - 0\right)}^{2} = 16$

From this equation, you know that the center of the circle will be located at (0;0).

${r}^{2} = 16$
$\therefore \sqrt{{r}^{2}} = \sqrt{16} \implies r = 4$.

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