Question

How do you graph `x^2+y^2=36`?

Answer 1

Please see below.

Explanation:

`x^2+y^2=36`

`hArr(x-0)^2+(y-0)^2=6^2`

This is nothing but locus of a point that moves so that its distance from point `(0,0)` is always `6`.

Hence, `x^2+y^2=36` is equation of a circle with center at `(0,0)` and radius `6` and accordingly we graph it.
graph{x^2+y^2=36 [-14, 14, -7, 7]}