How do you graph #x^2+y^2=36#?

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#x^2+y^2=36#

#hArr(x-0)^2+(y-0)^2=6^2#

This is nothing but locus of a point that moves so that its distance from point #(0,0)# is always #6#.

Hence, #x^2+y^2=36# is equation of a circle with center at #(0,0)# and radius #6# and accordingly we graph it.
graph{x^2+y^2=36 [-14, 14, -7, 7]}

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