Question

How do you graph `x^2+y^2-49=0`?

Answer 1

See answer below.

Explanation:

We compare this to the equation of a circle.

`(x-a)^2+(y-b)^2=r^2`

This is a circle, center `(a,b)` and radius `r`

In the equation

`x^2+y^2=49=7^2`

This is the equation of a circle, center `(0,0)` and radius `=7`

Draw this circle, center at the origin and radius `=7`

graph{x^2+y^2=49 [-18.02, 18.01, -9.01, 9.01]}