# How do you graph #x= -3(y-5)^2 +2#?

##### 1 Answer

The graph is an **"n" shape** . From the equations alone, we can tell for sure that this is a **quadratic equation** (either "u" or "n" shaped).

#### Explanation:

**Expand** the equation to get;

**Find turning points**and determine if they are maximum points or minimum points.- Next,
**find points of intersection**on the vertical and horizontal axis.

**Finding turning points** (

Hence,

The turning point is at coordinate **coefficient for the #y^2# is a negative** .

**Finding intersections** :

**Vertical axis** ;

Let

**Horizontal axis** :

Use

You should get something like this (scroll on the graph to get a better view):

PS: Feel free to ask away any questions.

** graph{-3x^2+30x-73 [-11.25, 11.25, -5.625, 5.625]} ** :