# How do you graph #x+3y=6# using intercepts?

##### 1 Answer

Jan 21, 2017

Find the intercepts by setting

#### Explanation:

Given:

#x+3y = 6#

we can find the intercepts by setting

In any case, putting

#3y = 6#

and hence

So the intersection with the

Putting

#x = 6#

So the intersection with the

Since there are no terms of degree

graph{(x+3y-6)(x^2+(y-2)^2-0.02)((x-6)^2+y^2-0.02) = 0 [-7.71, 12.29, -3.8, 6.2]}