# How do you graph #y = 1/2(x-3)(x+1)#?

##### 1 Answer

The plot is a concave upward parabola with a vertex at (1, -2) and roots at

#### Explanation:

Is a quadratic equation, so we know that the plot will be a parabola.

The equation as given is in **factored** form. If the factored form is written with all real numbers, it gives us the x-intercepts (roots) for the plot. If an equation is in factored form,

then, the x-intercepts for the graph are at

Here,

Finally, before we start to plot the parabola, it would be helpful to know the coordinates of the vertex of the parabola. Here's a trick! The

Here, the

The coordinates for the vertex of this parabola are at (1, -2).

Now we are ready to plot this parabola.

graph{1/2(x-3)(x+1) [-5, 5, -5, 5]}