Question

How do you graph `y=1/2sin2x`?

Answer 1

As below.

Explanation:

standard form of equation is `y = a sin(bx -c) + d`

Given : `y = (1/2) sin 2x`

`" Amplitude " = a = 1/2`

`"Period " = P = (2pi) / |b| = (2pi) / 2 = pi`

`Phase Shift" = -c / b = 0, "Vertical Shift " = d = 0`

graph{(1/2) sin (2x) [-10, 10, -5, 5]}