How do you graph #y>=-1/4x+3#?

1 Answer
Mar 31, 2015

You first graph #y=- 1/4 x+3# and then find where your "solution" space is.

Find some convenient #x#'s and determine the corresponding #y#'s
#x=-4->y=4->(-4,4)#
#x=0->y=3->(0,3)#
#x=8->y=1->(8,1)#
But any other #x#'s will do. Then connect these points by a straight line (two points would have been enough, but it's wise to have a third, just to check for mistakes: they should all line up).
graph{-0.25x+3 [-7.87, 12.13, -2.88, 7.12]}
Now everything above and including the line is part of the solution.