How do you graph #y= 1+ 5\sin \frac { \pi } { 2} ( x + 0.7)#?

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Answer 1 · 2018-06-19T06:47:45

As below.

Standard form of sine function is #y = A sin (Bx - C) + D#

#"Given " y = 5 sin ((pi/2)x + 0.7 (pi/2)) + 1#

#A = 5, B = pi/2, C = -0.7 (pi/2), D = 1#

#Amplitude = |A| = 5#

#"Period " = (2pi) / |B| = (2pi) / (pi/2) = 4#

#"Phase Shift " = - C / B = (0.7 (pi/2)) / (pi/2) = 0.7, 0.7 " to the right"#

#"Vertical Shift " = D = 1#

graph{5 sin ((pi/2)x + 0.7(pi/2)) + 1 [-10, 10, -5, 5]}