How do you graph #y=1.5x#?

1 Answer
Nov 18, 2016


graph{y=1.5x [-10, 10, -5, 5]}


The number being multiplied by #x# is the slope of the line. So, the slope of the line is calculated by rise/run. The rise is how up or down it goes from a certain point to another, and the run is how right or left it goes from a certain point to the other.

For this problem, the y-intercept is 0, but we don't write it out. Pretend that the 0 is invisible, but it is still these, so you already know the line passes through the origin(0,0).

For the slope of this line, the slope is positive, so it will be diagonal to the right side. Go up 1.5 units, because it is the rise, and go over 1, because the slope is positive.

I recommend you do this twice, so you can get a straight line. Also, don't remember to use a ruler.