Question

How do you graph `y =1/(x+3)`?

Answer 1

Solve the function for numbers around `x=-3`, since that is the domain function. Then connect the results you find, forming two curves.

Explanation:

This is a reciprocal function , so it has a domain restriction. Since no number can be divided by zero, we have to find the solution for `x+3=0`. That would be `-3`.
After that, we solve the function for numbers close to the restriction. The result should be two curves.
`f(-6)= -0.333`
`f(-5)=-0.5`
`f(-4)=-1`

`f(-2)=1`
`f(-1)=0.5`
`f(0)=0.333`
graph{1/(x+3) [-7, 1 -3, 3]}