# How do you graph y=2+3x?

Jul 10, 2018

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$y = 2 + \left(3 \cdot 0\right)$

$y = 2 + 0$

$y = 2$ or $\left(0 , 2\right)$

Second Point: For $x = 1$

$y = 2 + \left(3 \cdot 1\right)$

$y = 2 + 3$

$y = 5$ or $\left(1 , 5\right)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2-3x)(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}