# How do you graph #y=2+3x#?

##### 1 Answer

Jul 10, 2018

#### Answer:

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

**First Point:** For

**Second Point:** For

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2-3x)(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}