How do you graph #y=2+3x#?

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Answer 1 · 2018-07-10T14:03:21

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = 2 + (3 * 0)#

#y = 2 + 0#

#y = 2# or #(0, 2)#

Second Point: For #x = 1#

#y = 2 + (3 * 1)#

#y = 2 + 3#

#y = 5# or #(1, 5)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2-3x)(x^2+(y-2)^2-0.075)((x-1)^2+(y-5)^2-0.075)=0 [-20, 20, -10, 10]}