How do you graph #y = 2# by plotting points?

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Answer 1 · 2018-07-10T13:57:14

See a solution process below:

The equation #y = 2# says for any value of #x# the #y# value is #2#.

Therefore, two points on this line are:

#(-2, 2)# and #(2,2 )#

We can first plot these points:

graph{((x+2)^2+(y-2)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-2+0.000001x)((x+2)^2+(y-2)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Answer 2 · 2018-07-11T00:09:31

See below:

When we have an equation of the form

#y=c#, we know we are dealing with a horizontal line. No matter what #x# is, #y# will always be #2#.

Our graph, on the #y#-axis, will always be equal to #2#.

graph{y=0x+2 [-10, 10, -5, 5]}

Hope this helps!