# How do you graph y=2^(x+1)+3?

Aug 5, 2018

The new coordinates would be

$\left(- 2 , 3.5\right)$, $\left(- 1 , 4\right)$, $\left(0 , 5\right)$, $\left(1 , 7\right)$, $\left(2 , 11\right)$

#### Explanation:

First, you want to know some points for the parent function, $y = {2}^{x}$

• $\left(- 1 , .5\right)$
• $\left(0 , 1\right)$
• $\left(1 , 2\right)$
• $\left(2 , 4\right)$
• $\left(3 , 8\right)$

graph{2^x [-10, 10, -5, 5]}

Then we can look at this new equation and see that the y-intercept shifts up 3 from the $+ 3$, so all the y coordinates shift up $3$ as well.

We also can see that the x coordinates all shift left 1 from the $x + 1$. The new coordinates would be

• $\left(- 2 , 3.5\right)$
• $\left(- 1 , 4\right)$
• $\left(0 , 5\right)$
• $\left(1 , 7\right)$
• $\left(2 , 11\right)$

graph{2^(x+1) + 3 [-9.92, 10.08, -0.8, 9.2]}