How do you graph #y=2^(x+1)+3#?
1 Answer
Aug 5, 2018
The new coordinates would be
Explanation:
First, you want to know some points for the parent function,
#(-1,.5)# #(0,1)# #(1,2)# #(2,4)# #(3,8)#
graph{2^x [-10, 10, -5, 5]}
Then we can look at this new equation and see that the y-intercept shifts up 3 from the
We also can see that the x coordinates all shift left 1 from the
#(-2,3.5)# #(-1,4)# #(0,5)# #(1,7)# #(2,11)#
graph{2^(x+1) + 3 [-9.92, 10.08, -0.8, 9.2]}
