How do you graph: y = 2^x + 2?

1 Answer
Mar 15, 2018

Look at the explanation for this is a "how" question.

Explanation:

First you have to know how the equation y=a^x looks.
It looks like this:
graph{1.5^x [-83.3, 83.35, -41.66, 41.65]}
That is the general shape.

The range of every equation for y=a^x is (0, oo)
Also the point (0,1) exists on every exponential function because a^0 = 1
Also there is always a horizontal asymptote at y=0 unless there is a vertical shift, then it moves up or down.

Now plug in some points
x=-1, y=0.5
x=1, y=2
x=2, y=4

Now you just shift the whole graph up by 2
This makes the horizontal asymptote at y=2
graph{2^x+2 [-83.3, 83.35, -41.66, 41.65]}