How do you graph: #y = 2^x + 2#?

1 Answer
Mar 15, 2018

Answer:

Look at the explanation for this is a "how" question.

Explanation:

First you have to know how the equation #y=a^x# looks.
It looks like this:
graph{1.5^x [-83.3, 83.35, -41.66, 41.65]}
That is the general shape.

The range of every equation for #y=a^x# is #(0, oo)#
Also the point #(0,1)# exists on every exponential function because #a^0 = 1#
Also there is always a horizontal asymptote at #y=0# unless there is a vertical shift, then it moves up or down.

Now plug in some points
#x=-1, y=0.5#
#x=1, y=2#
#x=2, y=4#

Now you just shift the whole graph up by 2
This makes the horizontal asymptote at #y=2#
graph{2^x+2 [-83.3, 83.35, -41.66, 41.65]}