Question

How do you graph `y=2ln(x+1)`?

Answer 1

y is defined for `x> -1` and has a single zero at `x=0`

Explanation:

`y=2ln(x+1)`

`ln(x)` is defined for `x>0`
Hence `y` is defined for `x> -1`

`ln(1) =0`
Hence `ln(x+1) = 0` for `(x+1) = 1`
`:. y` has a single zero at `x=0`

The graph of `y` is shown below:

graph{2ln(x+1) [-10, 10, -5, 5]}