# How do you graph y =-3/7x-1/7 using the slope and intercept?

In this equation the $- \frac{1}{7}$ is the $y$-intercept. since when $x = 0$ $y = \frac{1}{7}$, so plot a point at $\left(0 , \frac{1}{7}\right)$.
The coefficient of $x$ is the gradient / slope of the line, in this case the gradient is $- \frac{3}{7}$, to plot a second point on the graph move along the $x$-axis by $3$ then go along the $y$-axis by $- 7$, the negative means go down on the $y$-axis. So plot a point at $\left(3 , - 7\right)$.
Now that we have a point at $\left(0 , \frac{1}{7}\right)$ and $\left(3 , - 7\right)$, connect the points drawing a straight line.