How do you graph #y = 3 tan (x/2)#?

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Answer 1 · 2018-07-19T02:08:27

See graph and explanation.

The period of tan kx is #pi/k#.

So, for y = 3 tan ( x/2 ), period is #pi/(1/2) = 2pi#.

The asymptotes for tan x are

#x = ( 2k + 1 )pi/2, k = 0, +-1, +_2, +-3, ...#.

Here, they are #x = ( 2k + 1 )pi, k = 0, +-1, +_2, +-3, ...#.

Graph of y = 3 tan ( x/2 )::

graph{y-3 tan (x/2)=0[-20 20 -10 10]}