How do you graph y=3 using slope intercept form?

Jun 12, 2017

A horizontal straight line through $\left(0 , 3\right)$ or any other value of $x$.
$y = 0 x + 3$

Explanation:

The equation of a straight line in line $\left(m\right)$ and intercept $\left(c\right)$ form is: $y = m x + c$

However, in this example $y$ is independent of $x$ so the slope is $0$. This equivalent to: $y = 3 \forall x \in \mathbb{R}$

Or: $y = 0 x + 3$

Hence, our graph is a horizontal straight line through $\left(0 , 3\right)$ or any other value of $x$.
graph{0x+3 [-6.086, 6.4, -0.7, 5.545]}