Question

How do you graph `y = 3( x + 1 )^2-4`?

Answer 1

graph{3(x+1)^2-4 [-10, 10, -5, 5]}

Explanation:

This equation is in vertex form, which is `a(x-h)^2+k`, in which `(h,k)` is the vertex.

In this case, the vertex for this equation is `(-1,4)`