How do you graph y=3(x+3)^2 - 3?

If you expand it you get $y = 3 {x}^{2} + 18 x + 24$

Explanation:

With graph

graph{3x^2+18x+24 [-10, 10, -5, 5]}

Sep 9, 2015

See the explanation section.

Explanation:

For $y = a {\left(x - h\right)}^{2} + k$ the vertex is $\left(h , k\right)$ and the graph opens from the vertex through the points $x = h \pm 1$ and $y = k + a$ That is, through the points $\left(h + 1 , k + a\right)$ and $\left(h - 1 , k + a\right)$

For $y = 3 {\left(x + 3\right)}^{2} - 3$, the vertex is $\left(- 3 , - 3\right)$ and with $a = 3$, the parabola opens upward through the points $x = - 3 \pm 1$ and $y = - 3 + 3 = 0$. That is, through the points $\left(- 2 , 0\right)$ and $\left(- 4 , 0\right)$