How do you graph #y=3sin(1/2)x#?

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Answer 1 · 2018-04-01T05:25:30

As below.

#y = 3 sin (x/2)#

Standard form of the equation is #y = A sin (Bx - C) + D#

#Amplitude = |A| = 3#

#"Period " = (2pi) / |B| = (2pi) / (1/2) = 4ppi#

#"Phase Shift " = C / B = 0#

#"Vertical Shift " = D = 0#

graph{3 sin(x/2) [-10, 10, -5, 5]}