How do you graph #y=3tan(1/2x)-2#?

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Answer 1 · 2018-08-02T15:57:01

As below.

#y = 3 tan (x/2) - 2#

Standard form of tangent function is #y = A tan(Bx - C) + D#

#A = 3, B = 1/2, C = 0, D = -2#

#Amplitude = NONE # for tangent function.

Period #= (pi) / |B| = pi / (1/2) = 2pi#

Phase Shift #= (-C) / B = 0#

Vertical Shift #= D = -2#

graph{3 tan(x/2) - 2 [-10, 10, -5, 5]}