How do you graph #y=3x+5#?

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Answer 1 · 2018-05-29T21:42:15

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (3 * 0) + 5#

#y = 0 + 5#

#y = 5# or #(0, 5)#

Second Point: For #x = 1#

#y = (3 * 1) + 5#

#y = 3 + 5#

#y = 8# or #(1, 8)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-5)^2-0.1)((x-1)^2+(y-8)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-3x-5)(x^2+(y-5)^2-0.1)((x-1)^2+(y-8)^2-0.1)=0 [-20, 20, -10, 10]}