# How do you graph #y=4+2/3x# on a coordinate grid?

##### 1 Answer

Jun 16, 2018

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

**First Point:** For

**Second Point:** For

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.1)((x-3)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 4 - (2/3)x)(x^2+(y-4)^2-0.1)((x-3)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}