# How do you graph y=4+2/3x on a coordinate grid?

Jun 16, 2018

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$y = 4 + \left(\frac{2}{3} \cdot 0\right)$

$y = 4 + 0$

$y = 4$ or $\left(0 , 4\right)$

Second Point: For $x = 3$

$y = 4 + \left(\frac{2}{3} \cdot 3\right)$

$y = 4 + \frac{6}{3}$

$y = 4 + 2$

$y = 6$ or $\left(3 , 6\right)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.1)((x-3)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 4 - (2/3)x)(x^2+(y-4)^2-0.1)((x-3)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}