How do you graph #y=4x+1# using slope and intercept?

1 Answer
Jun 6, 2017

Answer:

graph{y=4x+1 [-10, 10, -5, 5]}

Explanation:

Since the equation is linear/straight in the form #y=mx+c#, you can determine the slope/gradient (#m#) and y-intercept (#c#).

#m=4#
#c=1#

To graph this equation, you'll need to find 2 points on the line and join them together. We know one of the points is (0, 1) as the y-intercept is 1.

You can find another point by substituting an arbitrary number into #x# or #y# in the equation. In this example, I'll substitute 1 into #x# to find the y coordinate where the x coordinate is 1.

#y=4(1)+1#
#y=4+1#
#y=5#

So, the second point would be (1, 5).

If you join the points (0, 1) and (1, 5) on a graph, this would be the line of the equation.