How do you graph #y=4x+3# using slope intercept form?

1 Answer
Mar 3, 2017

Answer:

  1. Put a point at the y-intercept on the graph: #(0,3)#

  2. Move up #4# points in the #+y#-direction and move #1# point in the #+x#-direction and place a second point.

Explanation:

Slope intercept form: #y = mx + b#

where #m = "slope" = (Delta y)/(Delta x) = (y_2 - y_1)/(x_2 - x_1)#

and #b = y-"intercept": (0, b)#

  1. Put a point at the y-intercept on the graph: #(0,3)#
  2. Slope = #4 = 4/1 = (-4)/-1#

  3. Move up #4# points in the #+y#-direction and move #1# point in the #+x#-direction and place a second point.

  4. Draw a line that passes through the two points

graph{4x + 3 [-12.18, 10.32, -2.475, 8.775]}