# How do you graph y=4x+3 using slope intercept form?

Mar 3, 2017
1. Put a point at the y-intercept on the graph: $\left(0 , 3\right)$

2. Move up $4$ points in the $+ y$-direction and move $1$ point in the $+ x$-direction and place a second point.

#### Explanation:

Slope intercept form: $y = m x + b$

where $m = \text{slope} = \frac{\Delta y}{\Delta x} = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

and $b = y - \text{intercept} : \left(0 , b\right)$

1. Put a point at the y-intercept on the graph: $\left(0 , 3\right)$
2. Slope = $4 = \frac{4}{1} = \frac{- 4}{-} 1$

3. Move up $4$ points in the $+ y$-direction and move $1$ point in the $+ x$-direction and place a second point.

4. Draw a line that passes through the two points

graph{4x + 3 [-12.18, 10.32, -2.475, 8.775]}