How do you graph #y=5/8x-7/8#?

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Answer 1 · 2017-08-21T01:00:55

See a solution process below:

To graph a linear equation you find and plot two points for the the equation and then draw a line through the points:

For #x = 3#

#y = (5/8 * 3) - 7/8#

#y = 15/8 - 7/8#

#y = 8/8#

#y = 1# or #(3, 1)#

For #x = 11#

#y = (5/8 * 11) - 7/8#

#y = 55/8 - 7/8#

#y = 48/8#

#y = 6# or #(11, 6)#

We can first plot the points.

graph{((x-3)^2+(y-1)^2-0.125)((x-11)^2+(y-6)^2-0.125)=0 [-20, 20, -10, 10]}

We can now draw a line through the two points to graph the line:

graph{(y-5/8x+7/8)((x-3)^2+(y-1)^2-0.125)((x-11)^2+(y-6)^2-0.125)=0 [-20, 20, -10, 10]}