# How do you graph y=5sqrtx?

Aug 28, 2016

You asked "how do you graph". This has been provided.

#### Explanation:

Consider this example:

${2}^{2} = 4$

The thing is; $\left(- 2\right) \times \left(- 2\right) = + 4 \text{ so } \sqrt{4}$ could be -2

Also $\left(+ 2\right) \times \left(+ 2\right) = + 4 \text{ so } \sqrt{4}$ could be +2 as well

Thus we have $\sqrt{4} = \pm 2$
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So for your question:
$y = 5 \sqrt{x}$ in fact is $y = \pm 5 \sqrt{x}$

$\textcolor{m a \ge n t a}{\text{The trap}}$

Suppose $x$ is negative. Then the square root takes you into the realm of complex numbers.

$\textcolor{red}{\text{Assumption: "x" is not negative.}}$
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Build a table of values calculating what $y$ is for the selected values of $x$. Remembering that $x$ is not negative.

Note that for each value of $x$ there will be corresponding values of $\pm y$

Plot the points and draw a line through the points as best as you can.