Question

How do you graph `y=5x-5` by plotting points?

Answer 1

Below

Explanation:

For x-intercepts, let `y=0`

`0=5x-5`
`5=5x`
`x=1` SO `(1,0)`

For y-intercepts, let `x=0`

`y=5(0)-5`
`y=-5` SO `(0,-5)`

Plot those two points on your graph and join them together.

graph{5-5x [-10, 10, -5, 5]}

An alternate way to graph this is basically go let `x=1` and sub it into the equation to get your y value. Then go let `x=2` and sub it into the equation and so on

Personally, I prefer the whole "finding the x and y intercepts"