Question

How do you graph `y=8x-7`?

Answer 1

See below

Explanation:

This equation is in the slope-intercept form (and is my favourite when graphing a line). The general expression is:

`y=mx+b`, where `m="slope"="rise"/"run"` and `b=y`-intercept.

We have `y=8x-7` and so `m=8` and `b=-7`.

The `y`-intercept means that we have one point at `(0,-7)`:

graph{(x-0)^2+(y+7)^2-.5^2=0[-20,20,-10,10]}

We can do one more point using the slope. With `m=8`, it means we rise 8 for every 1 move "running" (moving to the right). We can now find another point:

`(0+1,-7+8)=(1,1)` and now let's graph that:

graph{((x-0)^2+(y+7)^2-.5^2)((x-1)^2+(y-1)^2-.5^2)=0[-20,20,-10,10]}

And lastly let's connect the dots with a line:

graph{((x-0)^2+(y+7)^2-.5^2)((x-1)^2+(y-1)^2-.5^2)(y-8x+7)=0[-20,20,-10,10]}