# How do you graph #y=8x-7#?

##### 1 Answer

Nov 26, 2017

See below

#### Explanation:

This equation is in the slope-intercept form (and is my favourite when graphing a line). The general expression is:

We have

The

graph{(x-0)^2+(y+7)^2-.5^2=0[-20,20,-10,10]}

We can do one more point using the slope. With

graph{((x-0)^2+(y+7)^2-.5^2)((x-1)^2+(y-1)^2-.5^2)=0[-20,20,-10,10]}

And lastly let's connect the dots with a line:

graph{((x-0)^2+(y+7)^2-.5^2)((x-1)^2+(y-1)^2-.5^2)(y-8x+7)=0[-20,20,-10,10]}