# How do you graph y=8x-7?

See below

#### Explanation:

This equation is in the slope-intercept form (and is my favourite when graphing a line). The general expression is:

$y = m x + b$, where $m = \text{slope"="rise"/"run}$ and $b = y$-intercept.

We have $y = 8 x - 7$ and so $m = 8$ and $b = - 7$.

The $y$-intercept means that we have one point at $\left(0 , - 7\right)$:

graph{(x-0)^2+(y+7)^2-.5^2=0[-20,20,-10,10]}

We can do one more point using the slope. With $m = 8$, it means we rise 8 for every 1 move "running" (moving to the right). We can now find another point:

$\left(0 + 1 , - 7 + 8\right) = \left(1 , 1\right)$ and now let's graph that:

graph{((x-0)^2+(y+7)^2-.5^2)((x-1)^2+(y-1)^2-.5^2)=0[-20,20,-10,10]}

And lastly let's connect the dots with a line:

graph{((x-0)^2+(y+7)^2-.5^2)((x-1)^2+(y-1)^2-.5^2)(y-8x+7)=0[-20,20,-10,10]}