How do you graph #y=cosx+tan(2x)#?

1 Answer
Dec 28, 2016

Socratic graph for two periods #2pi# is inserted.

Explanation:

The period of cos x is #2pi# and the period of tan (2x) is #pi/2#.

So, the period of cos x + tan 2x is #2pi#.

x = an odd mutiple of #pi/2# is an asymptote, in both directions

#uarr and darr#.

The inserted graph is for a double period #x in [-2pi, 2pi]#

x = 0 is the divider, for this double-period graph.

y-intercept is 0.752, nearly, from cos x + tan (2x) = 0.

graph{cos x + tan (2x) [-6.28, 6.28, -5, 5]}