How do you graph #y=lnx-1#?

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Answer 1 · 2016-09-22T11:27:13

The graph of #y# is the standard function #lnx# shifted one unit down the #y-#axis. #y# has a zero at #x=e#

#f(x)=lnx# has a vertical asymtote at #x=0# and a zero at #x=1#

In this question #y=f(x)-1# which simply shifts ("transforms") #f(x)# one unit down the #y-# axis.

To find the zero:

#y=lnx-1 =0 -> lnx =1#
#x=e^1=e#

Hence #y# has a zero at #x=e#

These features can be seen on the graph of #lnx-1# below:

graph{lnx-1 [-4.64, 15.36, -5.65, 4.35]}