Question

How do you graph `y = sec(3x + pi/2)`?

Answer 1

As below.

Explanation:

`y = sec(3x + (pi/2))`

Standard form of the equation is `y = A sec(Bx - C) + D`

`Amplitude = A = color(red)(" None") " for secant"`

`"Period " = (2pi) / |B| = (2pi) / 3`

`"Phase Shift " = -C / B = -(pi/2) / 3 = -pi/6, " " pi/6 " to the left"`

`"Vertical Shift " = D = 0`

graph{sec(3x + pi/2) [-10, 10, -5, 5]}